Корнеева Т.П. Сборник задач по физике. Механика 1. Задача 2.40
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Центростремительное ускорение земли равно
a
=
ω
2
R
{\displaystyle a=\omega ^{2}R}
Тогда
m
ω
2
R
=
G
m
M
R
2
{\displaystyle m\omega ^{2}R=G{\frac {mM}{R^{2}}}}
Откуда
M
=
ω
2
R
3
G
=
2.0
⋅
10
30
k
g
{\displaystyle M={\frac {\omega ^{2}R^{3}}{G}}=2.0\cdot 10^{30}kg}
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